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Great explanation, many thanks for your hard work

One of the greatest explanations, thank you so much

Thank you sir

its pronounced kirkoffffff not kirk chofff

"We are just gonna assume" 4:08 This was such happy moment. I was literally so confused like everyone was saying that the extension of both springs is same and ........ Now i got it

Even 14 years later your videos are helping me

So happy you're back!

Went from helping students in physics to helping people in the kitchen. legend

Question, for charge density, shouldn't we be using the volume of a sphere on the denom not 4pir^2?

AA vericem fizik 2 yi. Sağ olun hocam.

thank you 😭🙏

Legend

This guy has some problems in his brain or something, because he clearly isn't talking straight, mixing r1 and m1 and mumbling you one doesn't even understand what he is saying.

Really wish I knew this.

this was so helpful

Can i use the method if one spring is torsional spring and the other is translational spring and i need to find the k eq of the tow springs.

9:16 wait what did he do here?

Thañks sir for ur video has helped me so much 🙏

Hi, you helped me in physics so many times, I just wanted to see how you were doing, Hope you are having a wonderful life!! THANKS

bro knew I would need this 14 years ago.

He example KVI lavun solve karun dya please

Super explaining..👍

@lasseviren1 I am amazed of how simple you are able to explain things. What is your background and how do you manage to break down explanations so elegantly?

Thankes sir

Anyone in 2024?

An "in-depth" description of how the Tank Circuit delivers the energy from the capacitor to the coil (inductor) and then back to the capacitor. The "secret" of its operation has never been described before and all discussions have glossed-over "how and when and why" the capacitor gets fully discharged before the cycle starts again. Suppose the capacitor is charged and is placed across the inductor. Current will flow into the inductor and produce magnetic lines of force in the core that will cut all the other turns and produce a voltage in these turns that is opposite to the incoming voltage. This means the incoming voltage will see a voltage produced by the inductor that will be as high as 99% of the incoming voltage. This means the incoming voltage will appear as a very small voltage and it will increase the flux lines very slowly. The capacitor will keep supplying current but since the voltage across it is reducing, the current will be reducing and thus the flux will be expanding at a reduced rate. The back voltage produced by the expanding flux depends on the rate of expansion and since this expansion is getting less, the back voltage is reducing. The amazing thing is this: as the voltage of the capacitor decreases, the back voltage decreases and the current increases. I can explain it this way. Suppose you put a 9v battery across the coil, after a short time the flux will be a maximum but it will not be expanding flux and inductor will produce the maximum flux and take the maximum current. When the capacitor is almost fully discharged, the current will be a maximum and because the flux is not expanding, there will be no back voltage. So a point comes when the capacitor has no voltage across it and the inductor produces no voltage. This is the secret to how the oscillator works. Because the inductor has a very small resistance, it only takes a very small voltage to deliver a very high current and produce a very large amount of magnetic flux. But eventually this small voltage cannot maintain the flux and all the voltage and current-capability is taken from the capacitor. At this point in the cycle, the flux cannot be maintained and it starts to collapse. As it collapses, it can only produce a certain amount of current and this current charges the capacitor. In other words the capacitor controls the rate of collapse of the inductor and the voltage across the capacitor gradually increases. In actual fact, the inductor "can and will" produce a very large voltage during a collapse if nothing is connected to it and this is called a fly-back voltage. But since a capacitor is connected, the voltage can only rise as the capacitor allows it to rise. So it rises until the flux has almost fully collapsed and even at this point the collapsing flux is able to produce a voltage much higher than the voltage across the capacitor and that's why it can keep charging the capacitor right up to the point when the flux has almost completely collapsed. That's why the capacitor gets charged to almost the original voltage. Even the tiniest amount of flux will produce a charging voltage. But eventually the flux is zero and the voltage across the capacitor sees the inductor as a very small resistance and it starts to deliver a current. This current produces magnetic flux in all the turns of the winding and each turn produces a back voltage so that the actual magnetizing voltage is very small and thus only a very small current flows to create the second cycle. THE SECRET Here's the reason why the capacitor is able to deliver all its energy to the coil: As the voltage across the capacitor decreases, the coil can only produce a back voltage that is slightly less than the capacitor voltage. That's why the energy keeps flowing from the capacitor to the inductor. It is only when the capacitor cannot deliver any more current, that the circuit starts to change direction. Just before this occurs, the voltage of the capacitor can be very small because the resistance of the inductor comes into play since the back-voltage is very small and it is the back-voltage that turns the resistance of the coil into an inductance. Now we have a very small capacitance voltage being able to deliver a high current into a small resistance to maintain the magnetic field. Only when this voltage finally reduces to almost zero, does the circuit start to change direction. Now, going back in the other direction, why is the inductor able to keep charging the capacitor when it is nearly out of magnetic flux? The reason is this. If the capacitor was not connected, the inductor would be able to produce a very high voltage when the magnetic field is collapsing because the size of the back-voltage depends on the speed of the collapsing field. Even when the inductor is almost out of flux, it can produce a very high voltage when nothing is connected to it. That is: when no capacitor is connected, it will collapse very fast and produce a very high voltage. So, it is the capacitor that is controlling this voltage, BUT it is always slightly higher than the voltage across the capacitor so the charging keeps occurring until the inductor is finally out of flux. Don't forget, when the magnetic field of the inductor is collapsing, the voltage it is producing is in the opposite direction to the original voltage. This means the capacitor gets charged in the opposite direction. In the diagram above, the top rail is the supply rail and the bottom rail is connected to a transistor. If we connect a multimeter or digital CRO to the transistor, we will see the voltage reduce lower than rail voltage during half the cycle and then become higher than rail voltage during the second half of the cycle. This means the effective voltage at this point is TWICE RAIL VOLTAGE. The Tank Circuit can double the supply voltage !!

timeless legend 🔥🔥🔥🔥🔥🔥

14 years ago❤

Why i used to put 1/2 after the (y^2+a^2) ?

Thank you so much sir! These videos are so helpful. Keep up the great work!

I appreciate the more explicit RC time example. Like the Greek 'tau' for 63.3%. 🥳 Thank you.

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My textbook… almost every university textbook said that the motional emf=Blv not negative Blv. Your derivative makes sense but I’m confused for how inconsistent the equations are. Are you representing the induced motional emf or motions emf? I hope you read this to clarify my confusion.

It's 2024😮 and vodeo was made in 2014

Great video! However, sin is the largest at pi/2 not pi.

Made my life easier with this videos, thanks a lot sir

bars

Gracias por la explicación 👍

thank you so much sir

sir please make videos on integration, you are an angel, please make it, love from india

Thank you so much! All of your videos are fantastic and extremely helpful!

Another waycto differentiate the potiontal equation same result

This is like a physics lesson from a subdued Norm Macdonald. You even say "well, gosh" at 2:01. (But for real, this video answered my question!)

amazing thank you so much

allati yofilxar

skibidi araa lil bro

Thank u so much sir!😊

Love from INDIA ❤

Thank you so much. I am currently studying for an exam on Monday and it is late Friday so my only resources are online help. I was able to solve my own problem with 3 batteries and 4 resistors following your example. Thank you for the help.